What are the solutions to the equation factor x^2-8x+12=0 ?

The solutions to the equation factor x^2-8x+12=0 are x=2,x=6

Find the zeros of factor x^2-8x+12=0

The zeros of factor x^2-8x+12=0 are x=2,x=6

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x^{2} - 8 x + 12 = 0

x = 2, x = 6

Solution steps

x^{2} - 8 x + 12 = 0

Factor

x^{2} - 8 x + 12 : (x - 2) (x - 6)

(x - 2) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = 2, x = 6

x^{2} + 1 = 0

(x - 4) (1 + x) = 0

- 3 x^{2} + 5 x - 1 = 5 x^{2} - 8 x - 3

x^{2} - 25 x + 9

x^{2} - 2 x = 24

What are the solutions to the equation factor x^2-8x+12=0 ?
The solutions to the equation factor x^2-8x+12=0 are x=2,x=6
Find the zeros of factor x^2-8x+12=0
The zeros of factor x^2-8x+12=0 are x=2,x=6