What are the solutions to the equation 16z^2-40z+31=6 ?

The solutions to the equation 16z^2-40z+31=6 are z= 5/4

Find the zeros of 16z^2-40z+31=6

The zeros of 16z^2-40z+31=6 are z= 5/4

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16 z^{2} - 40 z + 31 = 6

z = \frac{5}{4}

Decimal

z = 1.25

Solution steps

16 z^{2} - 40 z + 31 = 6

Move

6

to the left side

16 z^{2} - 40 z + 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

z_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

z = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

z = \frac{5}{4}

The solution to the quadratic equation is:

z = \frac{5}{4}

- 0.25 x^{2} + 6 x + 20 = 0

y, x^{2} y^{2} + 5 x y = 14

6 x^{2} + 24 x - 126 = 0

4 = 3 x^{2} - 14 x + 4

- 4 a^{2} - 37 = - 137

What are the solutions to the equation 16z^2-40z+31=6 ?
The solutions to the equation 16z^2-40z+31=6 are z= 5/4
Find the zeros of 16z^2-40z+31=6
The zeros of 16z^2-40z+31=6 are z= 5/4