What are the solutions to the equation 10x^2+2x=-3x ?

The solutions to the equation 10x^2+2x=-3x are x=0,x=-1/2

Find the zeros of 10x^2+2x=-3x

The zeros of 10x^2+2x=-3x are x=0,x=-1/2

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10 x^{2} + 2 x = - 3 x

x = 0, x = - \frac{1}{2}

Decimal

x = 0, x = - 0.5

Solution steps

10 x^{2} + 2 x = - 3 x

Move

3 x

to the left side

10 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

5^{2} - 4 \cdot 10 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 10}, x_{2} = \frac{- 5 - 5}{2 \cdot 10}

x = \frac{- 5 + 5}{2 \cdot 10} : 0

x = \frac{- 5 - 5}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

y, 3 y^{2} - 2 x^{2} = 6 - 2 x y

3 x^{2} - 4 x + 4 = 0

x^{2} + 4 x - 32 = 0

11 x^{2} + 7 x = 3

0.69 x^{2} - 34 x + 435 = 600

What are the solutions to the equation 10x^2+2x=-3x ?
The solutions to the equation 10x^2+2x=-3x are x=0,x=-1/2
Find the zeros of 10x^2+2x=-3x
The zeros of 10x^2+2x=-3x are x=0,x=-1/2