What are the solutions to the equation roots x^2-x+4 ?

The solutions to the equation roots x^2-x+4 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

Find the zeros of roots x^2-x+4

The zeros of roots x^2-x+4 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

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roots

x^{2} - x + 4

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

Solution steps

x^{2} - x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 4 : 15 i

x_{1, 2} = \frac{- ( - 1 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 15 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 15 i}{2 \cdot 1} : \frac{1}{2} + i \frac{15}{2}

x = \frac{- ( - 1 ) - 15 i}{2 \cdot 1} : \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

9 x^{2} - 15 x - 6 = 0

(40 - x) (60 - x) = 800

2 x^{2} + 160 = 36 x

y, y^{2} + 2 y + 1 = 0

t, A t - \frac{( B t ^{2} )}{2} = 0

What are the solutions to the equation roots x^2-x+4 ?
The solutions to the equation roots x^2-x+4 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2
Find the zeros of roots x^2-x+4
The zeros of roots x^2-x+4 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2