What are the solutions to the equation solvefor t,At-((Bt^2))/2 =0 ?

The solutions to the equation solvefor t,At-((Bt^2))/2 =0 are t=0,t=(2A)/B ;\quad B\ne 0

Find the zeros of solvefor t,At-((Bt^2))/2 =0

The zeros of solvefor t,At-((Bt^2))/2 =0 are t=0,t=(2A)/B ;\quad B\ne 0

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solve for

t, A t - \frac{( B t ^{2} )}{2} = 0

t = 0, t = \frac{2 A}{B}; B \neq = 0

Solution steps

A t - \frac{( B t ^{2} )}{2} = 0

Multiply both sides by

2

- B t^{2} + 2 A t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 2 A \pm ( 2 A ) ^{2} - 4 ( - B ) \cdot 0}{2 ( - B )}

Simplify

(2 A)^{2} - 4 (- B) \cdot 0 : 2 A

t_{1, 2} = \frac{- 2 A \pm 2 A}{2 ( - B )}; B \neq = 0

Separate the solutions

t_{1} = \frac{- 2 A + 2 A}{2 ( - B )}, t_{2} = \frac{- 2 A - 2 A}{2 ( - B )}

t = \frac{- 2 A + 2 A}{2 ( - B )} : 0

t = \frac{- 2 A - 2 A}{2 ( - B )} : \frac{2 A}{B}

The solutions to the quadratic equation are:

t = 0, t = \frac{2 A}{B}; B \neq = 0

(2 x - 1) (x + 2) = 8 x - 4

3 x^{2} - 26 = 1

x^{2} - 3 x - 19 = 0

(x - 4)^{2} - 10 = (x - 1)^{2} - x^{2}

x^{2} + x + 3

What are the solutions to the equation solvefor t,At-((Bt^2))/2 =0 ?
The solutions to the equation solvefor t,At-((Bt^2))/2 =0 are t=0,t=(2A)/B ;\quad B\ne 0
Find the zeros of solvefor t,At-((Bt^2))/2 =0
The zeros of solvefor t,At-((Bt^2))/2 =0 are t=0,t=(2A)/B ;\quad B\ne 0