What are the solutions to the equation -x^2+10x+25=0 ?

The solutions to the equation -x^2+10x+25=0 are x=-5(sqrt(2)-1),x=5(1+sqrt(2))

Find the zeros of -x^2+10x+25=0

The zeros of -x^2+10x+25=0 are x=-5(sqrt(2)-1),x=5(1+sqrt(2))

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- x^{2} + 10 x + 25 = 0

x = - 5 (2 - 1), x = 5 (1 + 2)

Decimal

x = - 2.07106 \dots, x = 12.07106 \dots

Solution steps

- x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) \cdot 25}{2 ( - 1 )}

1 0^{2} - 4 (- 1) \cdot 25 = 102

x_{1, 2} = \frac{- 10 \pm 10 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 10 2}{2 ( - 1 )}, x_{2} = \frac{- 10 - 10 2}{2 ( - 1 )}

x = \frac{- 10 + 10 2}{2 ( - 1 )} : - 5 (2 - 1)

x = \frac{- 10 - 10 2}{2 ( - 1 )} : 5 (1 + 2)

The solutions to the quadratic equation are:

x = - 5 (2 - 1), x = 5 (1 + 2)

10 = 3 Q^{2} - 18 Q + 5

s^{2} + 4 s + 13

4 x^{2} + 11 x - 108 = 0

y, x^{4} y - 8 x y + 3 x y^{2} = 9

x^{2} = - 147

What are the solutions to the equation -x^2+10x+25=0 ?
The solutions to the equation -x^2+10x+25=0 are x=-5(sqrt(2)-1),x=5(1+sqrt(2))
Find the zeros of -x^2+10x+25=0
The zeros of -x^2+10x+25=0 are x=-5(sqrt(2)-1),x=5(1+sqrt(2))