What are the solutions to the equation h^2+19h=0 ?

The solutions to the equation h^2+19h=0 are h=0,h=-19

Find the zeros of h^2+19h=0

The zeros of h^2+19h=0 are h=0,h=-19

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h^{2} + 19 h = 0

h = 0, h = - 19

Solution steps

h^{2} + 19 h = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 0 = 19

h_{1, 2} = \frac{- 19 \pm 19}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 19 + 19}{2 \cdot 1}, h_{2} = \frac{- 19 - 19}{2 \cdot 1}

h = \frac{- 19 + 19}{2 \cdot 1} : 0

h = \frac{- 19 - 19}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

h = 0, h = - 19

3 x^{2} - 10 x = - 7

y^{2} = - 15

2 x^{2} + 8 x + 11 = 0

x^{2} = x + 30

π r^{2} h

What are the solutions to the equation h^2+19h=0 ?
The solutions to the equation h^2+19h=0 are h=0,h=-19
Find the zeros of h^2+19h=0
The zeros of h^2+19h=0 are h=0,h=-19