What are the solutions to the equation 4(x^2-5)+5=-3 ?

The solutions to the equation 4(x^2-5)+5=-3 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 4(x^2-5)+5=-3

The zeros of 4(x^2-5)+5=-3 are x=sqrt(3),x=-sqrt(3)

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4 (x^{2} - 5) + 5 = - 3

x = 3, x = - 3

Decimal

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

4 (x^{2} - 5) + 5 = - 3

Move

5

to the right side

4 (x^{2} - 5) = - 8

Divide both sides by

4

x^{2} - 5 = - 2

Move

5

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

7 x^{2} - 19 x - 6 = 0

4 x^{2} - 5 x = 6

s^{2} + 1.2 s + 1

a, a^{2} - 3 a y^{2} + 3 y^{4} - b = 0

- 25 x^{2} + 20 x - 4 = 0

What are the solutions to the equation 4(x^2-5)+5=-3 ?
The solutions to the equation 4(x^2-5)+5=-3 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 4(x^2-5)+5=-3
The zeros of 4(x^2-5)+5=-3 are x=sqrt(3),x=-sqrt(3)