What are the solutions to the equation solvefor y,y^2=x^3-x ?

The solutions to the equation solvefor y,y^2=x^3-x are y=sqrt(x^3-x),y=-sqrt(x^3-x)

Find the zeros of solvefor y,y^2=x^3-x

The zeros of solvefor y,y^2=x^3-x are y=sqrt(x^3-x),y=-sqrt(x^3-x)

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solve for

y, y^{2} = x^{3} - x

y = x^{3} - x, y = - x^{3} - x

Solution steps

y^{2} = x^{3} - x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{3} - x, y = - x^{3} - x

4 x^{2} + 12 x - 5

2 - 25 x^{2} = 625 x^{2}

y, y^{2} - 3 x^{2} = 0

4 a^{2} - 14 a + 13 = 2

2 x^{2} + 14 x + 11 = 0

What are the solutions to the equation solvefor y,y^2=x^3-x ?
The solutions to the equation solvefor y,y^2=x^3-x are y=sqrt(x^3-x),y=-sqrt(x^3-x)
Find the zeros of solvefor y,y^2=x^3-x
The zeros of solvefor y,y^2=x^3-x are y=sqrt(x^3-x),y=-sqrt(x^3-x)