What are the solutions to the equation 3(x+11)^2+12=0 ?

The solutions to the equation 3(x+11)^2+12=0 are x=2i-11,x=-2i-11

Find the zeros of 3(x+11)^2+12=0

The zeros of 3(x+11)^2+12=0 are x=2i-11,x=-2i-11

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3 (x + 11)^{2} + 12 = 0

x = 2 i - 11, x = - 2 i - 11

Solution steps

3 (x + 11)^{2} + 12 = 0

Move

12

to the right side

3 (x + 11)^{2} = - 12

Divide both sides by

3

(x + 11)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 11 = - 4 : x = 2 i - 11

Solve

x + 11 = - - 4 : x = - 2 i - 11

The solutions to the quadratic equation are:

x = 2 i - 11, x = - 2 i - 11

x^{2} + 3^{2} = 2 5^{2}

1 x + 3 x + 1 = 8 x - (- -) 3

(x + 2) \times (x - 4) = x + 2

2 x + 15 = - \frac{4}{5} x^{2} + 10 x

34 y^{2} - 835 y + 4875 = 0

What are the solutions to the equation 3(x+11)^2+12=0 ?
The solutions to the equation 3(x+11)^2+12=0 are x=2i-11,x=-2i-11
Find the zeros of 3(x+11)^2+12=0
The zeros of 3(x+11)^2+12=0 are x=2i-11,x=-2i-11