What are the solutions to the equation 160x^2+18x-9=0 ?

The solutions to the equation 160x^2+18x-9=0 are x= 3/16 ,x=-3/10

Find the zeros of 160x^2+18x-9=0

The zeros of 160x^2+18x-9=0 are x= 3/16 ,x=-3/10

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160 x^{2} + 18 x - 9 = 0

x = \frac{3}{16}, x = - \frac{3}{10}

Decimal

x = 0.1875, x = - 0.3

Solution steps

160 x^{2} + 18 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 160 ( - 9 )}{2 \cdot 160}

1 8^{2} - 4 \cdot 160 (- 9) = 78

x_{1, 2} = \frac{- 18 \pm 78}{2 \cdot 160}

Separate the solutions

x_{1} = \frac{- 18 + 78}{2 \cdot 160}, x_{2} = \frac{- 18 - 78}{2 \cdot 160}

x = \frac{- 18 + 78}{2 \cdot 160} : \frac{3}{16}

x = \frac{- 18 - 78}{2 \cdot 160} : - \frac{3}{10}

The solutions to the quadratic equation are:

x = \frac{3}{16}, x = - \frac{3}{10}

y, 4 y^{2} + x y - 2 x^{2} = 3

x^{2} + 5 x - 166.4 = 0

2 x - 5 - 3 x^{2} = 0

(4 - x)^{2} = 1

y, x^{2} + y^{2} = 6 x y

What are the solutions to the equation 160x^2+18x-9=0 ?
The solutions to the equation 160x^2+18x-9=0 are x= 3/16 ,x=-3/10
Find the zeros of 160x^2+18x-9=0
The zeros of 160x^2+18x-9=0 are x= 3/16 ,x=-3/10