What are the solutions to the equation 0=3(x-4)^2 ?

The solutions to the equation 0=3(x-4)^2 are x=4

Find the zeros of 0=3(x-4)^2

The zeros of 0=3(x-4)^2 are x=4

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0 = 3 (x - 4)^{2}

x = 4

Solution steps

0 = 3 (x - 4)^{2}

Switch sides

3 (x - 4)^{2} = 0

Divide both sides by

3

(x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 4 = 0 : x = 4

The solution to the quadratic equation is:

x = 4

4 x^{2} + 17 = 20 x

4 t^{2} - 19 t - 30 = 0

1 - 2 x^{2} - x = 0

5 t^{2} + 15 t + 7 = 0

9 d^{2} = 1

What are the solutions to the equation 0=3(x-4)^2 ?
The solutions to the equation 0=3(x-4)^2 are x=4
Find the zeros of 0=3(x-4)^2
The zeros of 0=3(x-4)^2 are x=4