What are the solutions to the equation 4t^2-19t-30=0 ?

The solutions to the equation 4t^2-19t-30=0 are t=6,t=-5/4

Find the zeros of 4t^2-19t-30=0

The zeros of 4t^2-19t-30=0 are t=6,t=-5/4

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4 t^{2} - 19 t - 30 = 0

t = 6, t = - \frac{5}{4}

Decimal

t = 6, t = - 1.25

Solution steps

4 t^{2} - 19 t - 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 ( - 30 )}{2 \cdot 4}

(- 19)^{2} - 4 \cdot 4 (- 30) = 29

t_{1, 2} = \frac{- ( - 19 ) \pm 29}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 19 ) + 29}{2 \cdot 4}, t_{2} = \frac{- ( - 19 ) - 29}{2 \cdot 4}

t = \frac{- ( - 19 ) + 29}{2 \cdot 4} : 6

t = \frac{- ( - 19 ) - 29}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

t = 6, t = - \frac{5}{4}

1 - 2 x^{2} - x = 0

5 t^{2} + 15 t + 7 = 0

9 d^{2} = 1

100 x^{2} - 10011 x - 10.11 = 0

(x + 2)^{2} - 4 x + 4 = 0

What are the solutions to the equation 4t^2-19t-30=0 ?
The solutions to the equation 4t^2-19t-30=0 are t=6,t=-5/4
Find the zeros of 4t^2-19t-30=0
The zeros of 4t^2-19t-30=0 are t=6,t=-5/4