What are the solutions to the equation x^2+2x-575=0 ?

The solutions to the equation x^2+2x-575=0 are x=23,x=-25

Find the zeros of x^2+2x-575=0

The zeros of x^2+2x-575=0 are x=23,x=-25

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x^{2} + 2 x - 575 = 0

x = 23, x = - 25

Solution steps

x^{2} + 2 x - 575 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 575 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 575) = 48

x_{1, 2} = \frac{- 2 \pm 48}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 48}{2 \cdot 1}, x_{2} = \frac{- 2 - 48}{2 \cdot 1}

x = \frac{- 2 + 48}{2 \cdot 1} : 23

x = \frac{- 2 - 48}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

x = 23, x = - 25

3 x^{2} + 17 = - 10 x + 9

x^{2} + 6 x - 100 = 6 x

120 = x + \frac{x ^{2}}{20}

d^{2} - 9 d + 11 = 0

n^{2} - 6 n = 0

What are the solutions to the equation x^2+2x-575=0 ?
The solutions to the equation x^2+2x-575=0 are x=23,x=-25
Find the zeros of x^2+2x-575=0
The zeros of x^2+2x-575=0 are x=23,x=-25