What are the solutions to the equation (xsqrt(3))^2+x^2=1 ?

The solutions to the equation (xsqrt(3))^2+x^2=1 are x= 1/2 ,x=-1/2

Find the zeros of (xsqrt(3))^2+x^2=1

The zeros of (xsqrt(3))^2+x^2=1 are x= 1/2 ,x=-1/2

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(x 3)^{2} + x^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal

x = 0.5, x = - 0.5

Solution steps

(x 3)^{2} + x^{2} = 1

Expand

(x 3)^{2} + x^{2} : 4 x^{2}

4 x^{2} = 1

Move

1

to the left side

4 x^{2} - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 1) = 4

x_{1, 2} = \frac{- 0 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 4}{2 \cdot 4}, x_{2} = \frac{- 0 - 4}{2 \cdot 4}

x = \frac{- 0 + 4}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 0 - 4}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{2}

4 y^{2} = - 12 y - 9

x^{2} = - 9 x - 20

19.25 = - 8.5 (2 r - 1.75)^{2}

x, x (2 x + 1) = 0

10 x^{2} + 125 = 5 x^{2} + 215

What are the solutions to the equation (xsqrt(3))^2+x^2=1 ?
The solutions to the equation (xsqrt(3))^2+x^2=1 are x= 1/2 ,x=-1/2
Find the zeros of (xsqrt(3))^2+x^2=1
The zeros of (xsqrt(3))^2+x^2=1 are x= 1/2 ,x=-1/2