What are the solutions to the equation 4y^2=-12y-9 ?

The solutions to the equation 4y^2=-12y-9 are y=-3/2

Find the zeros of 4y^2=-12y-9

The zeros of 4y^2=-12y-9 are y=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 y^{2} = - 12 y - 9

y = - \frac{3}{2}

Decimal

y = - 1.5

Solution steps

4 y^{2} = - 12 y - 9

Move

9

to the left side

4 y^{2} + 9 = - 12 y

Move

12 y

to the left side

4 y^{2} + 9 + 12 y = 0

Write in the standard form

a x^{2} + b x + c = 0

4 y^{2} + 12 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

y_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

y = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

y = - \frac{3}{2}

The solution to the quadratic equation is:

y = - \frac{3}{2}

x^{2} = - 9 x - 20

19.25 = - 8.5 (2 r - 1.75)^{2}

x, x (2 x + 1) = 0

10 x^{2} + 125 = 5 x^{2} + 215

6 x^{2} + 125 = 5 (x^{2} + 25)

What are the solutions to the equation 4y^2=-12y-9 ?
The solutions to the equation 4y^2=-12y-9 are y=-3/2
Find the zeros of 4y^2=-12y-9
The zeros of 4y^2=-12y-9 are y=-3/2