What are the solutions to the equation 14x^2-7=25 ?

The solutions to the equation 14x^2-7=25 are x= 4/(sqrt(7)),x=-4/(sqrt(7))

Find the zeros of 14x^2-7=25

The zeros of 14x^2-7=25 are x= 4/(sqrt(7)),x=-4/(sqrt(7))

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14 x^{2} - 7 = 25

x = \frac{4}{7}, x = - \frac{4}{7}

Decimal

x = 1.51185 \dots, x = - 1.51185 \dots

Solution steps

14 x^{2} - 7 = 25

Move

7

to the right side

14 x^{2} = 32

Divide both sides by

14

x^{2} = \frac{16}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{7}, x = - \frac{16}{7}

\frac{16}{7} = \frac{4}{7}

- \frac{16}{7} = - \frac{4}{7}

x = \frac{4}{7}, x = - \frac{4}{7}

(5 - x) (6 - x) = 2

v^{2} + 2 v - 24 = 0

4 (r - 1)^{2} = 8

(5 + x) (x + 1) = 4 (3 x - 4) + (x + 1) (3 x - 4)

4 x^{2} + 36 x = - 77

What are the solutions to the equation 14x^2-7=25 ?
The solutions to the equation 14x^2-7=25 are x= 4/(sqrt(7)),x=-4/(sqrt(7))
Find the zeros of 14x^2-7=25
The zeros of 14x^2-7=25 are x= 4/(sqrt(7)),x=-4/(sqrt(7))