What are the solutions to the equation 6x^2+49x+77=3x^2+28+47 ?

The solutions to the equation 6x^2+49x+77=3x^2+28+47 are x=(-49+sqrt(2377))/6 ,x=(-49-sqrt(2377))/6

Find the zeros of 6x^2+49x+77=3x^2+28+47

The zeros of 6x^2+49x+77=3x^2+28+47 are x=(-49+sqrt(2377))/6 ,x=(-49-sqrt(2377))/6

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6 x^{2} + 49 x + 77 = 3 x^{2} + 28 + 47

x = \frac{- 49 + 2377}{6}, x = \frac{- 49 - 2377}{6}

Decimal

x = - 0.04091 \dots, x = - 16.29241 \dots

Solution steps

6 x^{2} + 49 x + 77 = 3 x^{2} + 28 + 47

Refine

6 x^{2} + 49 x + 77 = 3 x^{2} + 75

Move

75

to the left side

6 x^{2} + 49 x + 2 = 3 x^{2}

Move

3 x^{2}

to the left side

3 x^{2} + 49 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

4 9^{2} - 4 \cdot 3 \cdot 2 = 2377

x_{1, 2} = \frac{- 49 \pm 2377}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 49 + 2377}{2 \cdot 3}, x_{2} = \frac{- 49 - 2377}{2 \cdot 3}

x = \frac{- 49 + 2377}{2 \cdot 3} : \frac{- 49 + 2377}{6}

x = \frac{- 49 - 2377}{2 \cdot 3} : \frac{- 49 - 2377}{6}

The solutions to the quadratic equation are:

x = \frac{- 49 + 2377}{6}, x = \frac{- 49 - 2377}{6}

10 - 5 x = 3 x^{2} - 3 (x - 3)

(3 y + 2) (y - 1) = y (y + 2)

- 9 x + 4 x^{2} + 3 = 0

- 2 x^{2} + x + 9 = 0

2 x^{2} + 4 x + 11 = 0

What are the solutions to the equation 6x^2+49x+77=3x^2+28+47 ?
The solutions to the equation 6x^2+49x+77=3x^2+28+47 are x=(-49+sqrt(2377))/6 ,x=(-49-sqrt(2377))/6
Find the zeros of 6x^2+49x+77=3x^2+28+47
The zeros of 6x^2+49x+77=3x^2+28+47 are x=(-49+sqrt(2377))/6 ,x=(-49-sqrt(2377))/6