What are the solutions to the equation 3(3x+5)^2-36=-21 ?

The solutions to the equation 3(3x+5)^2-36=-21 are x=(sqrt(5)-5)/3 ,x=(-sqrt(5)-5)/3

Find the zeros of 3(3x+5)^2-36=-21

The zeros of 3(3x+5)^2-36=-21 are x=(sqrt(5)-5)/3 ,x=(-sqrt(5)-5)/3

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3 (3 x + 5)^{2} - 36 = - 21

x = \frac{5 - 5}{3}, x = \frac{- 5 - 5}{3}

Decimal

x = - 0.92131 \dots, x = - 2.41202 \dots

Solution steps

3 (3 x + 5)^{2} - 36 = - 21

Move

36

to the right side

3 (3 x + 5)^{2} = 15

Divide both sides by

3

(3 x + 5)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 5 = 5 : x = \frac{5 - 5}{3}

Solve

3 x + 5 = - 5 : x = \frac{- 5 - 5}{3}

The solutions to the quadratic equation are:

x = \frac{5 - 5}{3}, x = \frac{- 5 - 5}{3}

x^{2} + 4 x = 8 x + 5

2 x^{2} - 1 \frac{7}{25} = 0

a x^{2} + 2 x + 1 = 0

2 x^{2} + 3 x - 1

25 x^{2} - 10 x = - 1

What are the solutions to the equation 3(3x+5)^2-36=-21 ?
The solutions to the equation 3(3x+5)^2-36=-21 are x=(sqrt(5)-5)/3 ,x=(-sqrt(5)-5)/3
Find the zeros of 3(3x+5)^2-36=-21
The zeros of 3(3x+5)^2-36=-21 are x=(sqrt(5)-5)/3 ,x=(-sqrt(5)-5)/3