What are the solutions to the equation 25x^2-10x=-1 ?

The solutions to the equation 25x^2-10x=-1 are x= 1/5

Find the zeros of 25x^2-10x=-1

The zeros of 25x^2-10x=-1 are x= 1/5

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25 x^{2} - 10 x = - 1

x = \frac{1}{5}

Decimal

x = 0.2

Solution steps

25 x^{2} - 10 x = - 1

Move

1

to the left side

25 x^{2} - 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

(- 10)^{2} - 4 \cdot 25 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 10 )}{2 \cdot 25}

\frac{- ( - 10 )}{2 \cdot 25} = \frac{1}{5}

x = \frac{1}{5}

The solution to the quadratic equation is:

x = \frac{1}{5}

x, y = 2 x^{2} - 12 x - 11

96 x^{2} + 660 x - 84 = 0

x^{2} - 4 x + 8 = 3

x^{2} + 2 = 4 x - 1

x^{2} + 4 x + 4 = 0

What are the solutions to the equation 25x^2-10x=-1 ?
The solutions to the equation 25x^2-10x=-1 are x= 1/5
Find the zeros of 25x^2-10x=-1
The zeros of 25x^2-10x=-1 are x= 1/5