What are the solutions to the equation h=((s^2))/b ?

The solutions to the equation h=((s^2))/b are s=sqrt(hb),s=-sqrt(hb);\quad b\ne 0

Find the zeros of h=((s^2))/b

The zeros of h=((s^2))/b are s=sqrt(hb),s=-sqrt(hb);\quad b\ne 0

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h = \frac{( s ^{2} )}{b}

s = hb, s = - hb; b \neq = 0

Solution steps

h = \frac{( s ^{2} )}{b}

Switch sides

\frac{( s ^{2} )}{b} = h

Multiply both sides by

b

s^{2} = hb; b \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = hb, s = - hb; b \neq = 0

y, x^{2} y - x y^{2} = 2

4 x^{2} + 3 x + 3 = 4

4 w^{2} + 20 w + 25 = 0

q^{2} - 7 q + 3 = - 2 q

x^{2} + 9 x + c

What are the solutions to the equation h=((s^2))/b ?
The solutions to the equation h=((s^2))/b are s=sqrt(hb),s=-sqrt(hb);\quad b\ne 0
Find the zeros of h=((s^2))/b
The zeros of h=((s^2))/b are s=sqrt(hb),s=-sqrt(hb);\quad b\ne 0