What are the solutions to the equation 5z^2-20z+25=z^2 ?

The solutions to the equation 5z^2-20z+25=z^2 are z= 5/2

Find the zeros of 5z^2-20z+25=z^2

The zeros of 5z^2-20z+25=z^2 are z= 5/2

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5 z^{2} - 20 z + 25 = z^{2}

z = \frac{5}{2}

Decimal

z = 2.5

Solution steps

5 z^{2} - 20 z + 25 = z^{2}

Move

z^{2}

to the left side

4 z^{2} - 20 z + 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

z_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

z = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

z = \frac{5}{2}

The solution to the quadratic equation is:

z = \frac{5}{2}

3 m^{2} - 4 m - 4 = m

4 x^{2} - 12 x + 9 = 36

- 5 v^{2} + 9 v + 1 = - 6 v^{2}

3 x^{2} + 28 x + 49 = 0

d^{2} + 10 d + 28 = 3

What are the solutions to the equation 5z^2-20z+25=z^2 ?
The solutions to the equation 5z^2-20z+25=z^2 are z= 5/2
Find the zeros of 5z^2-20z+25=z^2
The zeros of 5z^2-20z+25=z^2 are z= 5/2