What are the solutions to the equation x^2+10x=-1 ?

The solutions to the equation x^2+10x=-1 are x=-5+2sqrt(6),x=-5-2sqrt(6)

Find the zeros of x^2+10x=-1

The zeros of x^2+10x=-1 are x=-5+2sqrt(6),x=-5-2sqrt(6)

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x^{2} + 10 x = - 1

x = - 5 + 26, x = - 5 - 26

Decimal

x = - 0.10102 \dots, x = - 9.89897 \dots

Solution steps

x^{2} + 10 x = - 1

Move

1

to the left side

x^{2} + 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 1 = 46

x_{1, 2} = \frac{- 10 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 10 - 4 6}{2 \cdot 1}

x = \frac{- 10 + 4 6}{2 \cdot 1} : - 5 + 26

x = \frac{- 10 - 4 6}{2 \cdot 1} : - 5 - 26

The solutions to the quadratic equation are:

x = - 5 + 26, x = - 5 - 26

a^{2} + 2 ab + b^{2} - x^{2}

3.02 x^{2} + 16 x - 7.02 = 0

x^{2} + x - 12 = x + 4

16 x^{2} = 81

x^{2} - 5 x + 24 = 0

What are the solutions to the equation x^2+10x=-1 ?
The solutions to the equation x^2+10x=-1 are x=-5+2sqrt(6),x=-5-2sqrt(6)
Find the zeros of x^2+10x=-1
The zeros of x^2+10x=-1 are x=-5+2sqrt(6),x=-5-2sqrt(6)