What are the solutions to the equation 4^2+x^2=12^2 ?

The solutions to the equation 4^2+x^2=12^2 are x=8sqrt(2),x=-8sqrt(2)

Find the zeros of 4^2+x^2=12^2

The zeros of 4^2+x^2=12^2 are x=8sqrt(2),x=-8sqrt(2)

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4^{2} + x^{2} = 1 2^{2}

x = 82, x = - 82

Decimal

x = 11.31370 \dots, x = - 11.31370 \dots

Solution steps

4^{2} + x^{2} = 1 2^{2}

Move

4^{2}

to the right side

x^{2} = 128

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 128, x = - 128

128 = 82

- 128 = - 82

x = 82, x = - 82

(2 x + 3)^{2} = 9 + x

18 x^{2} + 476 x + 2400

3 k^{2} + 6 k = 105

x^{2} + 4 x - 5

3 (3 x + 6)^{2} - 46 = 5

What are the solutions to the equation 4^2+x^2=12^2 ?
The solutions to the equation 4^2+x^2=12^2 are x=8sqrt(2),x=-8sqrt(2)
Find the zeros of 4^2+x^2=12^2
The zeros of 4^2+x^2=12^2 are x=8sqrt(2),x=-8sqrt(2)