zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

根 x^2+ax+b

解答

根

x^{2} + a x + b

解答

x = \frac{- a + a ^{2} - 4 b}{2}, x = \frac{- a - a ^{2} - 4 b}{2}

求解步骤

x^{2} + a x + b

根与 X 轴相交

(y = 0)

x^{2} + a x + b = 0

使用求根公式求解

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot b}{2 \cdot 1}

化简

a^{2} - 4 \cdot 1 \cdot b : a^{2} - 4 b

x_{1, 2} = \frac{- a \pm a ^{2} - 4 b}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- a + a ^{2} - 4 b}{2 \cdot 1}, x_{2} = \frac{- a - a ^{2} - 4 b}{2 \cdot 1}

x = \frac{- a + a ^{2} - 4 b}{2 \cdot 1} : \frac{- a + a ^{2} - 4 b}{2}

x = \frac{- a - a ^{2} - 4 b}{2 \cdot 1} : \frac{- a - a ^{2} - 4 b}{2}

二次方程组的解是:

x = \frac{- a + a ^{2} - 4 b}{2}, x = \frac{- a - a ^{2} - 4 b}{2}

作图

流行的例子

2 x^{2} - x - 18 = 0

2 x^{2} + 4 x = - 12

x^{2} - 20 x + 72 = 0

2 x^{2} + 7 x + 2 = - 1

11 x^{2} = 7 - 2 x