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受欢迎的代数 >

2t^2+2t-1=0

解答

2 t^{2} + 2 t - 1 = 0

解答

t = \frac{- 1 + 3}{2}, t = - \frac{1 + 3}{2}

+1

十进制

t = 0.36602 \dots, t = - 1.36602 \dots

求解步骤

2 t^{2} + 2 t - 1 = 0

使用求根公式求解

t_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 1) = 23

t_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 2}

将解分隔开

t_{1} = \frac{- 2 + 2 3}{2 \cdot 2}, t_{2} = \frac{- 2 - 2 3}{2 \cdot 2}

t = \frac{- 2 + 2 3}{2 \cdot 2} : \frac{- 1 + 3}{2}

t = \frac{- 2 - 2 3}{2 \cdot 2} : - \frac{1 + 3}{2}

二次方程组的解是:

t = \frac{- 1 + 3}{2}, t = - \frac{1 + 3}{2}

作图

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