What are the solutions to the equation roots x^2+3x+1 ?

The solutions to the equation roots x^2+3x+1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

Find the zeros of roots x^2+3x+1

The zeros of roots x^2+3x+1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

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roots

x^{2} + 3 x + 1

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

Solution steps

x^{2} + 3 x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 1 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 5}{2 \cdot 1}

x = \frac{- 3 + 5}{2 \cdot 1} : \frac{- 3 + 5}{2}

x = \frac{- 3 - 5}{2 \cdot 1} : \frac{- 3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

4 X^{2} + 5 X - 51 = 0

4 x^{2} - 20 x = - 45

y, x^{2} y^{3} = 1

x^{2} + 5 x - 6 = 0

(3 v - 2) (2 v + 1) = 3 v^{2} - 11 v - 10

What are the solutions to the equation roots x^2+3x+1 ?
The solutions to the equation roots x^2+3x+1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2
Find the zeros of roots x^2+3x+1
The zeros of roots x^2+3x+1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2