What are the solutions to the equation (-5x-3)(2x-1)=0 ?

The solutions to the equation (-5x-3)(2x-1)=0 are x=-3/5 ,x= 1/2

Find the zeros of (-5x-3)(2x-1)=0

The zeros of (-5x-3)(2x-1)=0 are x=-3/5 ,x= 1/2

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(- 5 x - 3) (2 x - 1) = 0

x = - \frac{3}{5}, x = \frac{1}{2}

Decimal

x = - 0.6, x = 0.5

Solution steps

(- 5 x - 3) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 5 x - 3 = 0 or 2 x - 1 = 0

Solve

- 5 x - 3 = 0 : x = - \frac{3}{5}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{5}, x = \frac{1}{2}

- 12 X^{2} + 30 X + 18 = 0

A, A = \frac{1}{2} π r^{2}

10 x^{2} - 4 x + 1 = 6 x^{2}

16 x^{2} = 96 x - 150

8 z^{2} + 18 z - 7 = - 2

What are the solutions to the equation (-5x-3)(2x-1)=0 ?
The solutions to the equation (-5x-3)(2x-1)=0 are x=-3/5 ,x= 1/2
Find the zeros of (-5x-3)(2x-1)=0
The zeros of (-5x-3)(2x-1)=0 are x=-3/5 ,x= 1/2