What are the solutions to the equation x^2-x+6/25 =0 ?

The solutions to the equation x^2-x+6/25 =0 are x= 3/5 ,x= 2/5

Find the zeros of x^2-x+6/25 =0

The zeros of x^2-x+6/25 =0 are x= 3/5 ,x= 2/5

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x^{2} - x + \frac{6}{25} = 0

x = \frac{3}{5}, x = \frac{2}{5}

Decimal

x = 0.6, x = 0.4

Solution steps

x^{2} - x + \frac{6}{25} = 0

Multiply both sides by

25

25 x^{2} - 25 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 25 \cdot 6}{2 \cdot 25}

(- 25)^{2} - 4 \cdot 25 \cdot 6 = 5

x_{1, 2} = \frac{- ( - 25 ) \pm 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 5}{2 \cdot 25}, x_{2} = \frac{- ( - 25 ) - 5}{2 \cdot 25}

x = \frac{- ( - 25 ) + 5}{2 \cdot 25} : \frac{3}{5}

x = \frac{- ( - 25 ) - 5}{2 \cdot 25} : \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = \frac{2}{5}

\frac{1}{7} p^{2} = \frac{5}{7} p^{2} - 20

2 x^{2} + 12 x - 3

4.9 t^{2} + 6 t + 2 = 0

x^{2} + 4 x - 12

y, x^{2} + 3 y^{2} - 4 x + 24 y = - 52

What are the solutions to the equation x^2-x+6/25 =0 ?
The solutions to the equation x^2-x+6/25 =0 are x= 3/5 ,x= 2/5
Find the zeros of x^2-x+6/25 =0
The zeros of x^2-x+6/25 =0 are x= 3/5 ,x= 2/5