What are the solutions to the equation roots x^2-x+2 ?

The solutions to the equation roots x^2-x+2 are x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

Find the zeros of roots x^2-x+2

The zeros of roots x^2-x+2 are x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} - x + 2

x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{2} - x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 2 : 7 i

x_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7 i}{2 \cdot 1} : \frac{1}{2} + i \frac{7}{2}

x = \frac{- ( - 1 ) - 7 i}{2 \cdot 1} : \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

x^{2} + \frac{3}{2} x + \frac{9}{16} = 0

x^{2} + 8 x - 8 = 25

x^{2} - x - 30 = 0

918 = 5 t^{2} + 3 t + 280

25 n^{2} - 24 n + 6 = n

What are the solutions to the equation roots x^2-x+2 ?
The solutions to the equation roots x^2-x+2 are x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2
Find the zeros of roots x^2-x+2
The zeros of roots x^2-x+2 are x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2