What are the solutions to the equation (x^2)/2+4x=24 ?

The solutions to the equation (x^2)/2+4x=24 are x=4,x=-12

Find the zeros of (x^2)/2+4x=24

The zeros of (x^2)/2+4x=24 are x=4,x=-12

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\frac{x ^{2}}{2} + 4 x = 24

x = 4, x = - 12

Solution steps

\frac{x ^{2}}{2} + 4 x = 24

Multiply both sides by

2

x^{2} + 8 x = 48

Move

48

to the left side

x^{2} + 8 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 48) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 1}, x_{2} = \frac{- 8 - 16}{2 \cdot 1}

x = \frac{- 8 + 16}{2 \cdot 1} : 4

x = \frac{- 8 - 16}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 4, x = - 12

6 x^{2} + 5 x - 4 = 0

2 x^{2} + 3 x - 10 = 3 - x

4 x^{2} + 2 = 1

2 x^{2} = 5 x + 4

0 = 2 x^{2} - 64

What are the solutions to the equation (x^2)/2+4x=24 ?
The solutions to the equation (x^2)/2+4x=24 are x=4,x=-12
Find the zeros of (x^2)/2+4x=24
The zeros of (x^2)/2+4x=24 are x=4,x=-12