What are the solutions to the equation 1.5x^2+12x+24=0 ?

The solutions to the equation 1.5x^2+12x+24=0 are x=-4

Find the zeros of 1.5x^2+12x+24=0

The zeros of 1.5x^2+12x+24=0 are x=-4

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1.5 x^{2} + 12 x + 24 = 0

x = - 4

Solution steps

1.5 x^{2} + 12 x + 24 = 0

Multiply both sides by

10

15 x^{2} + 120 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 15 \cdot 240}{2 \cdot 15}

12 0^{2} - 4 \cdot 15 \cdot 240 = 0

x_{1, 2} = \frac{- 120 \pm 0}{2 \cdot 15}

x = \frac{- 120}{2 \cdot 15}

\frac{- 120}{2 \cdot 15} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

x^{2} - 8 x - 74 = 7

4 b^{2} - 5 b - 6 = - 2

x + 3 = x^{2} + 2 x + 1

x^{2} - 6 x - 3 = 0

2 a^{2} + 2 = - 5 a

What are the solutions to the equation 1.5x^2+12x+24=0 ?
The solutions to the equation 1.5x^2+12x+24=0 are x=-4
Find the zeros of 1.5x^2+12x+24=0
The zeros of 1.5x^2+12x+24=0 are x=-4