What are the solutions to the equation 5r^2-12r+6=2 ?

The solutions to the equation 5r^2-12r+6=2 are r=2,r= 2/5

Find the zeros of 5r^2-12r+6=2

The zeros of 5r^2-12r+6=2 are r=2,r= 2/5

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5 r^{2} - 12 r + 6 = 2

r = 2, r = \frac{2}{5}

Decimal

r = 2, r = 0.4

Solution steps

5 r^{2} - 12 r + 6 = 2

Move

2

to the left side

5 r^{2} - 12 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 4 = 8

r_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 5}, r_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 5}

r = \frac{- ( - 12 ) + 8}{2 \cdot 5} : 2

r = \frac{- ( - 12 ) - 8}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

r = 2, r = \frac{2}{5}

x^{2} = 0

x^{2} - 2 x = 48

12 = - 3 x^{2} + 16 x

x^{2} + 4 x = - 8

2 x^{2} + 8 x + 22 = 0

What are the solutions to the equation 5r^2-12r+6=2 ?
The solutions to the equation 5r^2-12r+6=2 are r=2,r= 2/5
Find the zeros of 5r^2-12r+6=2
The zeros of 5r^2-12r+6=2 are r=2,r= 2/5