What are the solutions to the equation 31w^2-40w+16=6w^2 ?

The solutions to the equation 31w^2-40w+16=6w^2 are w= 4/5

Find the zeros of 31w^2-40w+16=6w^2

The zeros of 31w^2-40w+16=6w^2 are w= 4/5

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31 w^{2} - 40 w + 16 = 6 w^{2}

w = \frac{4}{5}

Decimal

w = 0.8

Solution steps

31 w^{2} - 40 w + 16 = 6 w^{2}

Move

6 w^{2}

to the left side

25 w^{2} - 40 w + 16 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

w_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

w = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

w = \frac{4}{5}

The solution to the quadratic equation is:

w = \frac{4}{5}

5 x^{2} + 2 = - 7 x + 8

0 = x^{2} - 4 x + 13

1.5 z^{2} + 2 z = 0

x^{2} + 12 x + 27 = 0

3 x^{2} - 3 x = 6

What are the solutions to the equation 31w^2-40w+16=6w^2 ?
The solutions to the equation 31w^2-40w+16=6w^2 are w= 4/5
Find the zeros of 31w^2-40w+16=6w^2
The zeros of 31w^2-40w+16=6w^2 are w= 4/5