What are the solutions to the equation solvefor y,x^2+y^2=2xy ?

The solutions to the equation solvefor y,x^2+y^2=2xy are y=x

Find the zeros of solvefor y,x^2+y^2=2xy

The zeros of solvefor y,x^2+y^2=2xy are y=x

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solve for

y, x^{2} + y^{2} = 2 x y

y = x

Solution steps

x^{2} + y^{2} = 2 x y

Move

2 x y

to the left side

x^{2} + y^{2} - 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 2 x y + x^{2} = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 x ) \pm ( - 2 x ) ^{2} - 4 \cdot 1 \cdot x ^{2}}{2 \cdot 1}

(- 2 x)^{2} - 4 \cdot 1 \cdot x^{2} = 0

y_{1, 2} = \frac{- ( - 2 x ) \pm 0}{2 \cdot 1}

y = \frac{- ( - 2 x )}{2 \cdot 1}

Simplify

\frac{- ( - 2 x )}{2 \cdot 1} : x

y = x

The solution to the quadratic equation is:

y = x

u^{2} - 6 u + 1 = 0

z^{2} - 3 z - 11 = - 6 z

- 75 x^{2} - 15 x - 100 = - 150 x^{2} + 10 x + 250

- 2 x^{2} - x - 6 = 0

x, - 3^{2} + x^{2} = 1 0^{2}

What are the solutions to the equation solvefor y,x^2+y^2=2xy ?
The solutions to the equation solvefor y,x^2+y^2=2xy are y=x
Find the zeros of solvefor y,x^2+y^2=2xy
The zeros of solvefor y,x^2+y^2=2xy are y=x