What are the solutions to the equation x^2+14x-48=0 ?

The solutions to the equation x^2+14x-48=0 are x=-7+sqrt(97),x=-7-sqrt(97)

Find the zeros of x^2+14x-48=0

The zeros of x^2+14x-48=0 are x=-7+sqrt(97),x=-7-sqrt(97)

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x^{2} + 14 x - 48 = 0

x = - 7 + 97, x = - 7 - 97

Decimal

x = 2.84885 \dots, x = - 16.84885 \dots

Solution steps

x^{2} + 14 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 48) = 297

x_{1, 2} = \frac{- 14 \pm 2 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 97}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 97}{2 \cdot 1}

x = \frac{- 14 + 2 97}{2 \cdot 1} : - 7 + 97

x = \frac{- 14 - 2 97}{2 \cdot 1} : - 7 - 97

The solutions to the quadratic equation are:

x = - 7 + 97, x = - 7 - 97

x^{2} + 5 x - 2 = 3 x - 2

y, 9 x^{2} + 2 x y = 3 y^{2} + x^{2}

2 x^{2} - 465 x - 3600 = 0

(x - 7)^{2} = 60

5 x^{2} - 4 x + 4 = 5

What are the solutions to the equation x^2+14x-48=0 ?
The solutions to the equation x^2+14x-48=0 are x=-7+sqrt(97),x=-7-sqrt(97)
Find the zeros of x^2+14x-48=0
The zeros of x^2+14x-48=0 are x=-7+sqrt(97),x=-7-sqrt(97)