What are the solutions to the equation 2x^2-20x+46=0 ?

The solutions to the equation 2x^2-20x+46=0 are x=5+sqrt(2),x=5-sqrt(2)

Find the zeros of 2x^2-20x+46=0

The zeros of 2x^2-20x+46=0 are x=5+sqrt(2),x=5-sqrt(2)

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2 x^{2} - 20 x + 46 = 0

x = 5 + 2, x = 5 - 2

Decimal

x = 6.41421 \dots, x = 3.58578 \dots

Solution steps

2 x^{2} - 20 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 \cdot 46}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 \cdot 46 = 42

x_{1, 2} = \frac{- ( - 20 ) \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 2}{2 \cdot 2}, x_{2} = \frac{- ( - 20 ) - 4 2}{2 \cdot 2}

x = \frac{- ( - 20 ) + 4 2}{2 \cdot 2} : 5 + 2

x = \frac{- ( - 20 ) - 4 2}{2 \cdot 2} : 5 - 2

The solutions to the quadratic equation are:

x = 5 + 2, x = 5 - 2

8^{2} + x^{2} = 1 1^{2}

3 x^{2} - 26 x + 16 = 0

3 x^{2} + 6 x - 132 = 0

y, x^{2} - x y + y^{2} = 6

y, x^{2} - x y + y^{2} = 9

What are the solutions to the equation 2x^2-20x+46=0 ?
The solutions to the equation 2x^2-20x+46=0 are x=5+sqrt(2),x=5-sqrt(2)
Find the zeros of 2x^2-20x+46=0
The zeros of 2x^2-20x+46=0 are x=5+sqrt(2),x=5-sqrt(2)