What are the solutions to the equation -12q^2+3q+7=0 ?

The solutions to the equation -12q^2+3q+7=0 are q=-(-3+sqrt(345))/(24),q=(3+sqrt(345))/(24)

Find the zeros of -12q^2+3q+7=0

The zeros of -12q^2+3q+7=0 are q=-(-3+sqrt(345))/(24),q=(3+sqrt(345))/(24)

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- 12 q^{2} + 3 q + 7 = 0

q = - \frac{- 3 + 345}{24}, q = \frac{3 + 345}{24}

Decimal

q = - 0.64892 \dots, q = 0.89892 \dots

Solution steps

- 12 q^{2} + 3 q + 7 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 12 ) \cdot 7}{2 ( - 12 )}

3^{2} - 4 (- 12) \cdot 7 = 345

q_{1, 2} = \frac{- 3 \pm 345}{2 ( - 12 )}

Separate the solutions

q_{1} = \frac{- 3 + 345}{2 ( - 12 )}, q_{2} = \frac{- 3 - 345}{2 ( - 12 )}

q = \frac{- 3 + 345}{2 ( - 12 )} : - \frac{- 3 + 345}{24}

q = \frac{- 3 - 345}{2 ( - 12 )} : \frac{3 + 345}{24}

The solutions to the quadratic equation are:

q = - \frac{- 3 + 345}{24}, q = \frac{3 + 345}{24}

5 x^{2} + 9 x + 7 = 0

x^{2} + x = - 7

18 x = 2 x^{2}

3 x^{2} + 2 x - 15 = 0

3 x^{2} + 18 x - 81 = 0

What are the solutions to the equation -12q^2+3q+7=0 ?
The solutions to the equation -12q^2+3q+7=0 are q=-(-3+sqrt(345))/(24),q=(3+sqrt(345))/(24)
Find the zeros of -12q^2+3q+7=0
The zeros of -12q^2+3q+7=0 are q=-(-3+sqrt(345))/(24),q=(3+sqrt(345))/(24)