What are the solutions to the equation 4x^2-16x=-16 ?

The solutions to the equation 4x^2-16x=-16 are x=2

Find the zeros of 4x^2-16x=-16

The zeros of 4x^2-16x=-16 are x=2

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4 x^{2} - 16 x = - 16

x = 2

Solution steps

4 x^{2} - 16 x = - 16

Move

16

to the left side

4 x^{2} - 16 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 16}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 16 )}{2 \cdot 4}

\frac{- ( - 16 )}{2 \cdot 4} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x^{2} + 5 = 54

x^{2} + 4 x - 240 = 0

x, y + x^{2} + 4 z^{2} = 4

x, y^{3} - 2 y = x^{2}

a^{2} = 33

What are the solutions to the equation 4x^2-16x=-16 ?
The solutions to the equation 4x^2-16x=-16 are x=2
Find the zeros of 4x^2-16x=-16
The zeros of 4x^2-16x=-16 are x=2