What are the solutions to the equation 12x^2-104x+153=0 ?

The solutions to the equation 12x^2-104x+153=0 are x=(26+sqrt(217))/6 ,x=(26-sqrt(217))/6

Find the zeros of 12x^2-104x+153=0

The zeros of 12x^2-104x+153=0 are x=(26+sqrt(217))/6 ,x=(26-sqrt(217))/6

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12 x^{2} - 104 x + 153 = 0

x = \frac{26 + 217}{6}, x = \frac{26 - 217}{6}

Decimal

x = 6.78848 \dots, x = 1.87818 \dots

Solution steps

12 x^{2} - 104 x + 153 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 104 ) \pm ( - 104 ) ^{2} - 4 \cdot 12 \cdot 153}{2 \cdot 12}

(- 104)^{2} - 4 \cdot 12 \cdot 153 = 4217

x_{1, 2} = \frac{- ( - 104 ) \pm 4 217}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 104 ) + 4 217}{2 \cdot 12}, x_{2} = \frac{- ( - 104 ) - 4 217}{2 \cdot 12}

x = \frac{- ( - 104 ) + 4 217}{2 \cdot 12} : \frac{26 + 217}{6}

x = \frac{- ( - 104 ) - 4 217}{2 \cdot 12} : \frac{26 - 217}{6}

The solutions to the quadratic equation are:

x = \frac{26 + 217}{6}, x = \frac{26 - 217}{6}

6 x^{2} + 25 x + 25 = 0

5 y^{2} + 7 y - 3 = 4 y

x^{2} = \frac{3}{250}

x^{2} - 10 x + 36 = 0

u^{2} + 3 u + 2 = 0

What are the solutions to the equation 12x^2-104x+153=0 ?
The solutions to the equation 12x^2-104x+153=0 are x=(26+sqrt(217))/6 ,x=(26-sqrt(217))/6
Find the zeros of 12x^2-104x+153=0
The zeros of 12x^2-104x+153=0 are x=(26+sqrt(217))/6 ,x=(26-sqrt(217))/6