What are the solutions to the equation -2x^2-5x=7 ?

The solutions to the equation -2x^2-5x=7 are x=-5/4-i(sqrt(31))/4 ,x=-5/4+i(sqrt(31))/4

Find the zeros of -2x^2-5x=7

The zeros of -2x^2-5x=7 are x=-5/4-i(sqrt(31))/4 ,x=-5/4+i(sqrt(31))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 5 x = 7

x = - \frac{5}{4} - i \frac{31}{4}, x = - \frac{5}{4} + i \frac{31}{4}

Solution steps

- 2 x^{2} - 5 x = 7

Move

7

to the left side

- 2 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

Simplify

(- 5)^{2} - 4 (- 2) (- 7) : 31 i

x_{1, 2} = \frac{- ( - 5 ) \pm 31 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 31 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 31 i}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 31 i}{2 ( - 2 )} : - \frac{5}{4} - i \frac{31}{4}

x = \frac{- ( - 5 ) - 31 i}{2 ( - 2 )} : - \frac{5}{4} + i \frac{31}{4}

The solutions to the quadratic equation are:

x = - \frac{5}{4} - i \frac{31}{4}, x = - \frac{5}{4} + i \frac{31}{4}

s^{2} + 2 s - 6 = 0

3 p (5 p - 1) = 0

6 x^{2} + 17 x = 24 + 7 x

x^{2} + 0.6 x - 19.1 = 0

y, x^{2} + x y + y^{2} = 48

What are the solutions to the equation -2x^2-5x=7 ?
The solutions to the equation -2x^2-5x=7 are x=-5/4-i(sqrt(31))/4 ,x=-5/4+i(sqrt(31))/4
Find the zeros of -2x^2-5x=7
The zeros of -2x^2-5x=7 are x=-5/4-i(sqrt(31))/4 ,x=-5/4+i(sqrt(31))/4