What are the solutions to the equation 4x^2-8ax+5x-10a=0 ?

The solutions to the equation 4x^2-8ax+5x-10a=0 are x=2a,x=-5/4

Find the zeros of 4x^2-8ax+5x-10a=0

The zeros of 4x^2-8ax+5x-10a=0 are x=2a,x=-5/4

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4 x^{2} - 8 a x + 5 x - 10 a = 0

x = 2 a, x = - \frac{5}{4}

Solution steps

4 x^{2} - 8 a x + 5 x - 10 a = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + (- 8 a + 5) x - 10 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 a + 5 ) \pm ( - 8 a + 5 ) ^{2} - 4 \cdot 4 ( - 10 a )}{2 \cdot 4}

Simplify

(- 8 a + 5)^{2} - 4 \cdot 4 (- 10 a) : 8 a + 5

x_{1, 2} = \frac{- ( - 8 a + 5 ) \pm ( 8 a + 5 )}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 a + 5 ) + 8 a + 5}{2 \cdot 4}, x_{2} = \frac{- ( - 8 a + 5 ) - ( 8 a + 5 )}{2 \cdot 4}

x = \frac{- ( - 8 a + 5 ) + 8 a + 5}{2 \cdot 4} : 2 a

x = \frac{- ( - 8 a + 5 ) - ( 8 a + 5 )}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 2 a, x = - \frac{5}{4}

5 x^{2} - 9 x + 18 = 4 x^{2}

x^{2} + 3 = 0

2 v^{2} + 11 v + 13 = 0

3 x^{2} - 12 x + 21 = 0

4 x^{2} + 2 x = 5

What are the solutions to the equation 4x^2-8ax+5x-10a=0 ?
The solutions to the equation 4x^2-8ax+5x-10a=0 are x=2a,x=-5/4
Find the zeros of 4x^2-8ax+5x-10a=0
The zeros of 4x^2-8ax+5x-10a=0 are x=2a,x=-5/4