What are the solutions to the equation roots 3x^2+12x+12 ?

The solutions to the equation roots 3x^2+12x+12 are x=-2

Find the zeros of roots 3x^2+12x+12

The zeros of roots 3x^2+12x+12 are x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

3 x^{2} + 12 x + 12

x = - 2

Solution steps

3 x^{2} + 12 x + 12

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} + 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 12 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 3}

x = \frac{- 12}{2 \cdot 3}

\frac{- 12}{2 \cdot 3} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

15 = x^{2} - 34

- 36 y^{2} + 36 y + 1 = 0

y, x^{3} y^{2} - 5 x^{2} y + x = 1

6 x^{2} - x + 1 = x^{2} + x + 4

y, x^{2} - 6 x y + y^{2} = 6

What are the solutions to the equation roots 3x^2+12x+12 ?
The solutions to the equation roots 3x^2+12x+12 are x=-2
Find the zeros of roots 3x^2+12x+12
The zeros of roots 3x^2+12x+12 are x=-2