What are the solutions to the equation 1/2 x^2+7x+20=0 ?

The solutions to the equation 1/2 x^2+7x+20=0 are x=-4,x=-10

Find the zeros of 1/2 x^2+7x+20=0

The zeros of 1/2 x^2+7x+20=0 are x=-4,x=-10

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\frac{1}{2} x^{2} + 7 x + 20 = 0

x = - 4, x = - 10

Solution steps

\frac{1}{2} x^{2} + 7 x + 20 = 0

Multiply both sides by

2

x^{2} + 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6}{2 \cdot 1}

x = \frac{- 14 + 6}{2 \cdot 1} : - 4

x = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

(x - 2)^{2} = 10

5 x^{2} - 16 = 8 x

6 x^{2} - 12 x - 90 = 2

\frac{x ^{2}}{2} = 1

9 x - 5 x^{2} = 0

What are the solutions to the equation 1/2 x^2+7x+20=0 ?
The solutions to the equation 1/2 x^2+7x+20=0 are x=-4,x=-10
Find the zeros of 1/2 x^2+7x+20=0
The zeros of 1/2 x^2+7x+20=0 are x=-4,x=-10