What are the solutions to the equation 4x^2+23=19x ?

The solutions to the equation 4x^2+23=19x are x= 19/8+i(sqrt(7))/8 ,x= 19/8-i(sqrt(7))/8

Find the zeros of 4x^2+23=19x

The zeros of 4x^2+23=19x are x= 19/8+i(sqrt(7))/8 ,x= 19/8-i(sqrt(7))/8

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4 x^{2} + 23 = 19 x

x = \frac{19}{8} + i \frac{7}{8}, x = \frac{19}{8} - i \frac{7}{8}

Solution steps

4 x^{2} + 23 = 19 x

Move

19 x

to the left side

4 x^{2} + 23 - 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 19 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 \cdot 23}{2 \cdot 4}

Simplify

(- 19)^{2} - 4 \cdot 4 \cdot 23 : 7 i

x_{1, 2} = \frac{- ( - 19 ) \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 19 ) - 7 i}{2 \cdot 4}

x = \frac{- ( - 19 ) + 7 i}{2 \cdot 4} : \frac{19}{8} + i \frac{7}{8}

x = \frac{- ( - 19 ) - 7 i}{2 \cdot 4} : \frac{19}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = \frac{19}{8} + i \frac{7}{8}, x = \frac{19}{8} - i \frac{7}{8}

60 x^{2} - 14 = 0

2 q^{2} - 44 q = - 14

4 - 36 x^{2} = 0

2 x^{2} - 1 = 17

x^{2} - 0.025 \cdot x - 0.075 = 0

What are the solutions to the equation 4x^2+23=19x ?
The solutions to the equation 4x^2+23=19x are x= 19/8+i(sqrt(7))/8 ,x= 19/8-i(sqrt(7))/8
Find the zeros of 4x^2+23=19x
The zeros of 4x^2+23=19x are x= 19/8+i(sqrt(7))/8 ,x= 19/8-i(sqrt(7))/8