What are the solutions to the equation (x+1)^2-1 1/3 =0 ?

The solutions to the equation (x+1)^2-1 1/3 =0 are x= 2/(sqrt(3))-1,x=-2/(sqrt(3))-1

Find the zeros of (x+1)^2-1 1/3 =0

The zeros of (x+1)^2-1 1/3 =0 are x= 2/(sqrt(3))-1,x=-2/(sqrt(3))-1

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(x + 1)^{2} - 1 \frac{1}{3} = 0

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

Decimal

x = 0.15470 \dots, x = - 2.15470 \dots

Solution steps

(x + 1)^{2} - 1 \frac{1}{3} = 0

Convert mixed numbers to improper fractions:

1 \frac{1}{3} = \frac{4}{3}

(x + 1)^{2} - \frac{4}{3} = 0

Move

\frac{4}{3}

to the right side

(x + 1)^{2} = \frac{4}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = \frac{4}{3} : x = \frac{2}{3} - 1

Solve

x + 1 = - \frac{4}{3} : x = - \frac{2}{3} - 1

The solutions to the quadratic equation are:

x = \frac{2}{3} - 1, x = - \frac{2}{3} - 1

x, (x + 8)^{2} = 16

y, y^{2} + x^{2} = 0

x^{2} - 6 x - 33 = - 4 x + 2

8 p^{2} + 8 p - 5 = 0

- 2 x^{2} + 4 x + 6 = 15

What are the solutions to the equation (x+1)^2-1 1/3 =0 ?
The solutions to the equation (x+1)^2-1 1/3 =0 are x= 2/(sqrt(3))-1,x=-2/(sqrt(3))-1
Find the zeros of (x+1)^2-1 1/3 =0
The zeros of (x+1)^2-1 1/3 =0 are x= 2/(sqrt(3))-1,x=-2/(sqrt(3))-1