What are the solutions to the equation n^2-30=-n ?

The solutions to the equation n^2-30=-n are n=5,n=-6

Find the zeros of n^2-30=-n

The zeros of n^2-30=-n are n=5,n=-6

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n^{2} - 30 = - n

n = 5, n = - 6

Solution steps

n^{2} - 30 = - n

Move

n

to the left side

n^{2} - 30 + n = 0

Write in the standard form

a x^{2} + b x + c = 0

n^{2} + n - 30 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 30) = 11

n_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 1 + 11}{2 \cdot 1}, n_{2} = \frac{- 1 - 11}{2 \cdot 1}

n = \frac{- 1 + 11}{2 \cdot 1} : 5

n = \frac{- 1 - 11}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 5, n = - 6

4 b^{2} - 5 b - 6 = - 2

- 6 x^{2} - 119 x - 875 = x - 5

x^{2} + 3 x + \frac{9}{4}

x^{2} + 3 x - \frac{27}{4} = 0

a^{2} - 4 a + 6 = 0

What are the solutions to the equation n^2-30=-n ?
The solutions to the equation n^2-30=-n are n=5,n=-6
Find the zeros of n^2-30=-n
The zeros of n^2-30=-n are n=5,n=-6