What are the solutions to the equation 3x^2+25x+8=0 ?

The solutions to the equation 3x^2+25x+8=0 are x=-1/3 ,x=-8

Find the zeros of 3x^2+25x+8=0

The zeros of 3x^2+25x+8=0 are x=-1/3 ,x=-8

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3 x^{2} + 25 x + 8 = 0

x = - \frac{1}{3}, x = - 8

Decimal

x = - 0.33333 \dots, x = - 8

Solution steps

3 x^{2} + 25 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

2 5^{2} - 4 \cdot 3 \cdot 8 = 23

x_{1, 2} = \frac{- 25 \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 25 + 23}{2 \cdot 3}, x_{2} = \frac{- 25 - 23}{2 \cdot 3}

x = \frac{- 25 + 23}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 25 - 23}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 8

x^{2} + 2 x = - 2 x - 5

3 y - y^{2} - 4 = 0

s^{2} + 14 s + 2 = 0

6 x^{2} + x - 5 = 0

- x - x^{2} = 0

What are the solutions to the equation 3x^2+25x+8=0 ?
The solutions to the equation 3x^2+25x+8=0 are x=-1/3 ,x=-8
Find the zeros of 3x^2+25x+8=0
The zeros of 3x^2+25x+8=0 are x=-1/3 ,x=-8