What are the solutions to the equation 3x^2+18x=-18 ?

The solutions to the equation 3x^2+18x=-18 are x=-3+sqrt(3),x=-3-sqrt(3)

Find the zeros of 3x^2+18x=-18

The zeros of 3x^2+18x=-18 are x=-3+sqrt(3),x=-3-sqrt(3)

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3 x^{2} + 18 x = - 18

x = - 3 + 3, x = - 3 - 3

Decimal

x = - 1.26794 \dots, x = - 4.73205 \dots

Solution steps

3 x^{2} + 18 x = - 18

Move

18

to the left side

3 x^{2} + 18 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 18 = 63

x_{1, 2} = \frac{- 18 \pm 6 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 6 3}{2 \cdot 3}, x_{2} = \frac{- 18 - 6 3}{2 \cdot 3}

x = \frac{- 18 + 6 3}{2 \cdot 3} : - 3 + 3

x = \frac{- 18 - 6 3}{2 \cdot 3} : - 3 - 3

The solutions to the quadratic equation are:

x = - 3 + 3, x = - 3 - 3

x^{2} - x - 1 = 0

(2 x - 1)^{2} = - x^{2} - 12 x + 5

a^{2} - 2 a = 63

\frac{1}{2} x^{2} + 2 x + \frac{1}{10} = 0

10 x^{2} + 15 x + 7 = 0

What are the solutions to the equation 3x^2+18x=-18 ?
The solutions to the equation 3x^2+18x=-18 are x=-3+sqrt(3),x=-3-sqrt(3)
Find the zeros of 3x^2+18x=-18
The zeros of 3x^2+18x=-18 are x=-3+sqrt(3),x=-3-sqrt(3)