What are the solutions to the equation 4q^2+q+1=-3q ?

The solutions to the equation 4q^2+q+1=-3q are q=-1/2

Find the zeros of 4q^2+q+1=-3q

The zeros of 4q^2+q+1=-3q are q=-1/2

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4 q^{2} + q + 1 = - 3 q

q = - \frac{1}{2}

Decimal

q = - 0.5

Solution steps

4 q^{2} + q + 1 = - 3 q

Move

3 q

to the left side

4 q^{2} + 4 q + 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

q_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

q = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

q = - \frac{1}{2}

The solution to the quadratic equation is:

q = - \frac{1}{2}

0 = 2 x^{2} - 8 x

10 n^{2} + 15 n - 25 = 6 n^{2}

x, z = 2 x^{2} - 4 y^{2}

\times (- 16) y^{2} = 0

x^{2} + 50 x - 30000 = 0

What are the solutions to the equation 4q^2+q+1=-3q ?
The solutions to the equation 4q^2+q+1=-3q are q=-1/2
Find the zeros of 4q^2+q+1=-3q
The zeros of 4q^2+q+1=-3q are q=-1/2